title: "TABLE_PRIVILEGES (Transact-SQL) | Microsoft Docs" ms.custom: "" ms.date: "03/15/2017" ms.prod: "sql" ms.prod_service: "database-engine, sql-database" ms.service: "" ms.component: "system-information-schema-views" ms.reviewer: "" ms.suite: "sql" ms.technology:
- "database-engine" ms.tgt_pltfrm: "" ms.topic: "language-reference" f1_keywords:
- "TABLE_PRIVILEGES_TSQL"
- "TABLE_PRIVILEGES" dev_langs:
- "TSQL" helpviewer_keywords:
- "INFORMATION_SCHEMA.TABLE_PRIVILEGES view"
- "TABLE_PRIVILEGES view" ms.assetid: 70269d26-b085-4a98-8a9f-b4742c2848bd caps.latest.revision: 30 author: "edmacauley" ms.author: "edmaca" manager: "craigg" ms.workload: "Inactive" monikerRange: "= azuresqldb-current || >= sql-server-2016 || = sqlallproducts-allversions"
[!INCLUDEtsql-appliesto-ss2008-asdb-xxxx-xxx-md]
Returns one row for each table privilege that is granted to or granted by the current user in the current database.
To retrieve information from these views, specify the fully qualified name of **INFORMATION_SCHEMA.**view_name.
| Column name | Data type | Description |
|---|---|---|
| GRANTOR | nvarchar(128) | Privilege grantor. |
| GRANTEE | nvarchar(128) | Privilege grantee. |
| TABLE_CATALOG | nvarchar(128) | Table qualifier. |
| TABLE_SCHEMA | nvarchar(128) | Name of schema that contains the table. ** Important ** Do not use INFORMATION_SCHEMA views to determine the schema of an object. The only reliable way to find the schema of a object is to query the sys.objects catalog view. |
| TABLE_NAME | sysname | Table name. |
| PRIVILEGE_TYPE | varchar(10) | Type of privilege. |
| IS_GRANTABLE | varchar(3) | Specifies whether the grantee can grant permissions to others. |
System Views (Transact-SQL)
Information Schema Views (Transact-SQL)
sys.objects (Transact-SQL)
sys.database_permissions (Transact-SQL)
sys.server_permissions (Transact-SQL)