title: "COLUMN_PRIVILEGES (Transact-SQL) | Microsoft Docs" ms.custom: "" ms.date: "03/15/2017" ms.prod: "sql" ms.prod_service: "database-engine, sql-database" ms.service: "" ms.component: "system-information-schema-views" ms.reviewer: "" ms.suite: "sql" ms.technology:
- "database-engine" ms.tgt_pltfrm: "" ms.topic: "language-reference" f1_keywords:
- "COLUMN_PRIVILEGES"
- "COLUMN_PRIVILEGES_TSQL" dev_langs:
- "TSQL" helpviewer_keywords:
- "COLUMN_PRIVILEGES view"
- "INFORMATION_SCHEMA.COLUMN_PRIVILEGES view" ms.assetid: 8ae29a85-2b77-48db-a2b9-a1720287b271 caps.latest.revision: 32 author: "edmacauley" ms.author: "edmaca" manager: "craigg" ms.workload: "Inactive" monikerRange: "= azuresqldb-current || >= sql-server-2016 || = sqlallproducts-allversions"
[!INCLUDEtsql-appliesto-ss2008-asdb-xxxx-xxx-md]
Returns one row for each column that has a privilege that is either granted to or granted by the current user in the current database.
To retrieve information from these views, specify the fully qualified name of **INFORMATION_SCHEMA.**view_name.
| Column name | Data type | Description |
|---|---|---|
| GRANTOR | nvarchar(128) | Privilege grantor. |
| GRANTEE | nvarchar(128) | Privilege grantee. |
| TABLE_CATALOG | nvarchar(128) | Table qualifier. |
| TABLE_SCHEMA | nvarchar(128) | Name of schema that contains the table. ** Important ** Do not use INFORMATION_SCHEMA views to determine the schema of an object. The only reliable way to find the schema of a object is to query the sys.objects catalog view. |
| TABLE_NAME | sysname | Table name. |
| COLUMN_NAME | sysname | Column name. |
| PRIVILEGE_TYPE | varchar(10) | Type of privilege. |
| IS_GRANTABLE | varchar(3) | Specifies whether the grantee can grant permissions to others. |
System Views (Transact-SQL)
Information Schema Views (Transact-SQL)
sys.sql_modules (Transact-SQL)
sys.objects (Transact-SQL)
sys.database_permissions (Transact-SQL)
sys.server_permissions (Transact-SQL)